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sulekhaswe...@gmail.com  
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 More options Jul 2, 4:31 am
Newsgroups: rec.puzzles
From: sulekhaswe...@gmail.com
Date: Wed, 2 Jul 2008 01:31:58 -0700 (PDT)
Local: Wed, Jul 2 2008 4:31 am
Subject: multiply
Hi,

suppose a is any non zero natural number ,
then a x 5 = a/2 x 10  is n't it ?


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Richard Heathfield  
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 More options Jul 2, 4:39 am
Newsgroups: rec.puzzles
From: Richard Heathfield <r...@see.sig.invalid>
Date: Wed, 02 Jul 2008 08:39:22 +0000
Local: Wed, Jul 2 2008 4:39 am
Subject: Re: multiply
sulekhaswe...@gmail.com said:

> Hi,

> suppose a is any non zero natural number ,
> then a x 5 = a/2 x 10  is n't it ?

It depends on the number representation you are using.

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google Groups users, please read: <http://improve-usenet.org/>
"Usenet is a strange place" - dmr 29 July 1999


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CBFalconer  
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 More options Jul 2, 10:45 am
Newsgroups: rec.puzzles
From: CBFalconer <cbfalco...@yahoo.com>
Date: Wed, 02 Jul 2008 10:45:11 -0400
Local: Wed, Jul 2 2008 10:45 am
Subject: Re: multiply

sulekhaswe...@gmail.com wrote:

> suppose a is any non zero natural number ,
> then a x 5 = a/2 x 10  is n't it ?

Only if a is even

--
 [mail]: Chuck F (cbfalconer at maineline dot net)
 [page]: <http://cbfalconer.home.att.net>
            Try the download section.


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Nishant Shukla  
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 More options Jul 2, 11:50 am
Newsgroups: rec.puzzles
From: Nishant Shukla <nick...@gmail.com>
Date: Wed, 2 Jul 2008 08:50:22 -0700 (PDT)
Local: Wed, Jul 2 2008 11:50 am
Subject: Re: multiply
On Jul 2, 4:31 am, sulekhaswe...@gmail.com wrote:

> Hi,

> suppose a is any non zero natural number ,
> then a x 5 = a/2 x 10  is n't it ?

this statement is true:
'a' times 5 = ('a' divided by 2) times 10

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Willem  
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 More options Jul 2, 11:56 am
Newsgroups: rec.puzzles
From: Willem <wil...@stack.nl>
Date: Wed, 2 Jul 2008 15:56:31 +0000 (UTC)
Local: Wed, Jul 2 2008 11:56 am
Subject: Re: multiply
Nishant Shukla wrote:

) On Jul 2, 4:31 am, sulekhaswe...@gmail.com wrote:
)> Hi,
)>
)> suppose a is any non zero natural number ,
)> then a x 5 = a/2 x 10  is n't it ?
)
) this statement is true:
) 'a' times 5 = ('a' divided by 2) times 10

What does ('a' divided by 2) mean for natural numbers ?

If I ask someone: "What is 5 divided by 2", then
he could answer: "2, with a remainder of 1"

SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
            made in the above text. For all I know I might be
            drugged or something..
            No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT


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Richard Heathfield  
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 More options Jul 2, 12:47 pm
Newsgroups: rec.puzzles
From: Richard Heathfield <r...@see.sig.invalid>
Date: Wed, 02 Jul 2008 16:47:57 +0000
Local: Wed, Jul 2 2008 12:47 pm
Subject: Re: multiply
CBFalconer said:

> sulekhaswe...@gmail.com wrote:

>> suppose a is any non zero natural number ,
>> then a x 5 = a/2 x 10  is n't it ?

> Only if a is even

No, it's true for odd a (and even for a=0, despite the exception in the
OP).

Let a=7, for example. a * 5 = 35, and a/2 * 10 = 10a/2 = 5a = 35.

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google Groups users, please read: <http://improve-usenet.org/>
"Usenet is a strange place" - dmr 29 July 1999


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Mark Brader  
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 More options Jul 2, 12:53 pm
Newsgroups: rec.puzzles
From: m...@vex.net (Mark Brader)
Date: Wed, 02 Jul 2008 11:53:25 -0500
Local: Wed, Jul 2 2008 12:53 pm
Subject: Re: multiply

>>> suppose a is any non zero natural number ,
>>> then a x 5 = a/2 x 10  is n't it ?
>> Only if a is even
> No, it's true for odd a ...

Depends on whether or not it's intended that the intermediate results
are also required to be natural numbers.
--
Mark Brader   |  "But [he] had already established his own reputation
Toronto       |   as someone who wrote poetry that mentioned the el."
m...@vex.net   |                                           --Al Kriman

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dgates  
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 More options Jul 2, 1:29 pm
Newsgroups: rec.puzzles
From: dgates <dga...@somedomain.com>
Date: Wed, 02 Jul 2008 10:29:46 -0700
Local: Wed, Jul 2 2008 1:29 pm
Subject: Re: multiply
On Wed, 2 Jul 2008 15:56:31 +0000 (UTC), Willem <wil...@stack.nl>
wrote:

>Nishant Shukla wrote:
>) On Jul 2, 4:31 am, sulekhaswe...@gmail.com wrote:
>)> Hi,
>)>
>)> suppose a is any non zero natural number ,
>)> then a x 5 = a/2 x 10  is n't it ?
>)
>) this statement is true:
>) 'a' times 5 = ('a' divided by 2) times 10

>What does ('a' divided by 2) mean for natural numbers ?

>If I ask someone: "What is 5 divided by 2", then
>he could answer: "2, with a remainder of 1"

Hmm, and what would he say if you asked "What is '2, with a remainder
of 1' multiplied by 10?"   :-)

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Richard Heathfield  
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 More options Jul 2, 2:42 pm
Newsgroups: rec.puzzles
From: Richard Heathfield <r...@see.sig.invalid>
Date: Wed, 02 Jul 2008 18:42:41 +0000
Local: Wed, Jul 2 2008 2:42 pm
Subject: Re: multiply
Mark Brader said:

>>>> suppose a is any non zero natural number ,
>>>> then a x 5 = a/2 x 10  is n't it ?

>>> Only if a is even

>> No, it's true for odd a ...

> Depends on whether or not it's intended that the intermediate results
> are also required to be natural numbers.

And on whether we are allowed to rearrange the equation. In mathematics, it
is normal to be granted such licence, provided it doesn't break any rules.
(It is in quietly breaking such rules that paradoxists arrive at some of
their curios.)

--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google users: <http://www.cpax.org.uk/prg/writings/googly.php>
"Usenet is a strange place" - dmr 29 July 1999


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Willem  
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 More options Jul 2, 3:22 pm
Newsgroups: rec.puzzles
From: Willem <wil...@stack.nl>
Date: Wed, 2 Jul 2008 19:22:11 +0000 (UTC)
Local: Wed, Jul 2 2008 3:22 pm
Subject: Re: multiply
Richard Heathfield wrote:

) And on whether we are allowed to rearrange the equation. In mathematics, it
) is normal to be granted such licence, provided it doesn't break any rules.
) (It is in quietly breaking such rules that paradoxists arrive at some of
) their curios.)

In the natural numbers, the division operator is such that you would break
some rules when rearranging equations.  I don't know offhand what they are
called, but I'm sure there are those more knowledgable who do.

SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
            made in the above text. For all I know I might be
            drugged or something..
            No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT


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Willem  
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 More options Jul 2, 3:25 pm
Newsgroups: rec.puzzles
From: Willem <wil...@stack.nl>
Date: Wed, 2 Jul 2008 19:25:08 +0000 (UTC)
Local: Wed, Jul 2 2008 3:25 pm
Subject: Re: multiply
dgates wrote:

) Hmm, and what would he say if you asked "What is '2, with a remainder
) of 1' multiplied by 10?"   :-)

Err, he would probably say that that doesn't make sense.

What is '5, with a remainder of 3' multiplied by 10 ?

SaSW, Willem
--
Disclaimer: I am in no way responsible for any of the statements
            made in the above text. For all I know I might be
            drugged or something..
            No I'm not paranoid. You all think I'm paranoid, don't you !
#EOT


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Simon Tatham  
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 More options Jul 2, 3:44 pm
Newsgroups: rec.puzzles
From: Simon Tatham <ana...@pobox.com>
Date: 02 Jul 2008 20:44:01 +0100 (BST)
Local: Wed, Jul 2 2008 3:44 pm
Subject: Re: multiply

> Mark Brader said:
>> Depends on whether or not it's intended that the intermediate results
>> are also required to be natural numbers.

Richard Heathfield  <r...@see.sig.invalid> wrote:

> And on whether we are allowed to rearrange the equation. In mathematics, it
> is normal to be granted such licence, provided it doesn't break any rules.

Yes, but that's precisely avoiding the question: Mark's point is
that he is stating what might be an implicit rule in this case,
which (if so) rearranging the equation would break.

The rationale behind rearranging and simplifying an equation is that
you apply transformations which do not affect the answer - or lack
of answer - given by the equation. That's the principle on which you
decide what rearrangements are valid in the first place. _If_ (as
Mark suggests is a possibility) we are constrained to work entirely
within the natural numbers and thus dividing an odd number by two is
forbidden, then we may not simplify "divide by two and then multiply
by ten" into "multiply by five", precisely _because_ the latter
would yield a result in cases where the former does not. You can't
get around such a restriction by citing rearrangement, because by
definition if the rearrangement gets you round a restriction then it
wasn't permitted anyway.

It is certainly true that naively rearranging this particular
equation can turn it into one which yields the same answer in all
cases where the original _did_ yield an answer and which also
produces answers with an internal consistency in some additional
cases, and this sort of possibility has historically tended to
inspire mathematicians to search for an expanded algebraic structure
which contains the previous one and in which more rearrangements
become valid and more equations soluble. Such processes have been
responsible for extending the natural numbers into integers,
rationals, reals, complex numbers and no end of rings, fields,
groups and more exotic stuff still. But none of that excuses the
breaking of the rules that bind you here and now in any given
situation; they merely suggest that _after_ you've finished solving
this particular problem and are no longer bound by its rules, then
there's an interesting area in which you might like to do further
research.
--
Simon Tatham         "A cynic is a person who smells flowers and
<ana...@pobox.com>    immediately looks around for a coffin."


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Mike Williams  
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 More options Jul 2, 3:46 pm
Newsgroups: rec.puzzles
From: Mike Williams <nos...@econym.demon.co.uk>
Date: Wed, 2 Jul 2008 20:46:43 +0100
Local: Wed, Jul 2 2008 3:46 pm
Subject: Re: multiply
Wasn't it Willem who wrote:

>Richard Heathfield wrote:
>) And on whether we are allowed to rearrange the equation. In mathematics, it
>) is normal to be granted such licence, provided it doesn't break any rules.
>) (It is in quietly breaking such rules that paradoxists arrive at some of
>) their curios.)

>In the natural numbers, the division operator is such that you would break
>some rules when rearranging equations.  I don't know offhand what they are
>called, but I'm sure there are those more knowledgable who do.

I think you're looking for the word "associative".

If a set is associative under multiplication, it means that
        (a * b) * c  = a * (b * c)
for all a, b and c in the set.

Thus:   (a/2 * 2) * 5  =  a/2 * (2 * 5)

The natural numbers are associative under multiplication.

So if "a/2" is allowed to have any meaning for odd naturals, and
conforms to the expected behaviour  (a/2 * 2) = a  then we're OK.

--
Mike Williams
Gentleman of Leisure


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